How to Convert Acceleration of 2400 Volt
- 1). Suppose you have a mass of 0.01 grams with a Coulomb of charge, and it's in a constant electric field (as exists between capacitor plates, for example). Suppose further that the potential difference between the two plates is 2400 volts. Suppose further that the distance between the two plates is 0.03 meters. So an electron would have to travel 3 centimeters to get from the negatively charged plate to the positively charged plate.
- 2). Solve for the work performed on a charge over a distance of 3cm through a potential difference of 2400V. Since voltage = work/charge = Fd and the charge is 1 C, then F = 2400V/0.03m = 80,000 Newtons. You could treat the force as constant over the length of d, since the electric field E is constant between capacitor plates.
- 3). Determine the acceleration of the charge by using Newton's second law. F=ma becomes 80,000N = 0.00001kg * a, where the asterisk * indicates multiplication. So acceleration a is 8 billion meters per second squared. By the time it hits the opposite plate, it will be going about 22 km per second, or 0.01 percent of the speed of light.
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